leetcode: Valid Phone Numbers 通过不了。求解

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https://leetcode.com/problems/valid-phone-numbers/

Given a text file file.txt that contains list of phone numbers (one per line), write a one liner bash script to print all valid phone numbers.

You may assume that a valid phone number must appear in one of the following two formats: (xxx) xxx-xxxx or xxx-xxx-xxxx. (x means a digit)

You may also assume each line in the text file must not contain leading or trailing white spaces.

For example, assume that file.txt has the following content:

987-123-4567
123 456 7890
[phone]

Your script should output the following valid phone numbers:

987-123-4567
[phone]

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我的答案是：
grep -E '\d\d\d-\d\d\d-\d\d\d\d|\(\d\d\d\)\s*\d\d\d-\d\d\d\d' file.txt

系统提示：
Submission Result: Wrong Answer
Input: 123-456-7891
Output:
Expected: 123-456-7891

但是在我的本机上，明明可以grep出来啊。
百思不得其解。求指导。

[msg7086]

帮你在我本机测了一下，返回的是空的。

[msg7086]

顺便我把 grep -E 改成 grep -P 以后就能拿到结果了。

[18000rpm]

又是正则的版本问题
osx -E 能出来，ubuntu 下 -E 不行

grep's default mode is (iirc) POSIX regex, and \d is pcre.
http://stackoverflow.com/a/6901221/1019566

[yangqi]

egrep '^(\([0-9]{3}\)\s|[0-9]{3}-)[0-9]{3}-[0-9]{4}$' file.txt

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@msg7086
@18000rpm
@yangqi
非常感谢！了解了。