推荐学习书目
› Learn Python the Hard Way
Python Sites
› PyPI - Python Package Index
› http://diveintopython.org/toc/index.html
› Pocoo
值得关注的项目
› PyPy
› Celery
› Jinja2
› Read the Docs
› gevent
› pyenv
› virtualenv
› Stackless Python
› Beautiful Soup
› 结巴中文分词
› Green Unicorn
› Sentry
› Shovel
› Pyflakes
› pytest
Python 编程
› pep8 Checker
Styles
› PEP 8
› Google Python Style Guide
› Code Style from The Hitchhiker's Guide
这是一个创建于 2538 天前的主题，其中的信息可能已经有所发展或是发生改变。
主要 py 文件码源:
import scrapy
from myfirst.items import MyfirstItem
class TestSpider(scrapy.Spider):
name = 'test'
part_url = 'https://www.qiushibaike.com/imgrank/'
page = 'page/'
def start_requests(self):
for page_number in range(1, 2, 1):
if page_number == 1:
yield self.make_requests_from_url(self.part_url)
else:
yield self.make_requests_from_url(self.part_url + self.page + str(page_number) + "/")
def parse(self, response):
item = MyfirstItem()
item["img_url"] = response.xpath("//div[@class='thumb']/a/img/@src")
for url in item["img_url"]:
print(url)
url 打印出来:
<Selector xpath="//div[@class='thumb']/a/img/@src" data='//pic.qiushibaike.com/system/pictures/11'>
实际地址比 data 的要长
import scrapy
from myfirst.items import MyfirstItem
class TestSpider(scrapy.Spider):
name = 'test'
part_url = 'https://www.qiushibaike.com/imgrank/'
page = 'page/'
def start_requests(self):
for page_number in range(1, 2, 1):
if page_number == 1:
yield self.make_requests_from_url(self.part_url)
else:
yield self.make_requests_from_url(self.part_url + self.page + str(page_number) + "/")
def parse(self, response):
item = MyfirstItem()
item["img_url"] = response.xpath("//div[@class='thumb']/a/img/@src")
for url in item["img_url"]:
print(url)
url 打印出来:
<Selector xpath="//div[@class='thumb']/a/img/@src" data='//pic.qiushibaike.com/system/pictures/11'>
实际地址比 data 的要长
 |
1
rabbbit 2017-12-05 23:04:46 +08:00  1
太长时间没用不太记得了
试试 response.xpath("//div[@class='thumb']/a/img/@src").extract() |
 |
2
Lwf1995 OP 是的,谢谢,我来查查 extract()
|
 |
3
simp1e 2017-12-05 23:28:12 +08:00
去掉最前面两个斜杠。。
print (url[2:]) |
 |
5
likeshu 2017-12-06 09:38:02 +08:00
XPATH
|
 |
6
mrzys 2017-12-12 14:32:29 +08:00
最简单的方法，f12，在 elements 右键，然后找到 copy，在找到 copy xpath
|
 |
7
qq583708076 2017-12-14 10:45:16 +08:00
response.xpath("//div[@class='thumb']/a/img/@src") .extract_first()
|
 |
8
lp77885544 2019-04-08 19:10:43 +08:00
楼主最后怎么解决的呢？
|
Select Language